Option Explicit
Dim a As Integer
Dim b As Integer
Dim c As Integer
Dim d As Integer
Const vbKeyDecPt = 46
Private Sub cmdexit_Click()
End
End Sub
Private Sub cmdnext_Click()
c = Val(txtans.Text)
If c = a + b Then
lblmessage.Caption = "Correct Answer"
Text2.Text = d + 1
ElseIf txtans.Text = "" Then
lblmessage.Caption = "Pls. Input Answer"
Else
lblmessage.Caption = "Wrong Answer!"
End If
d = Text2.Text
a = (50 * Rnd)
b = (49 * Rnd)
lblnum1.Caption = a
lblnum2.Caption = b
txtans.Text = ""
End Sub
Private Sub Command1_Click()
Text2.Text = ""
End Sub
Private Sub Command2_Click()
End Sub
Private Sub Form_Load()
cmdnext.Enabled = True
a = (50 * Rnd)
b = (49 * Rnd)
lblnum1.Caption = a
lblnum2.Caption = b
End Sub
Private Sub txtans_KeyPress(KeyAscii As Integer)
If (KeyAscii %26gt;= vbKey0 And KeyAscii %26lt;= vbKey9) Or KeyAscii = vbKeyDecPt Or KeyAscii = vbKeyBack Then
Exit Sub
Else
KeyAscii = 0
Beep
End If
End
Kindly help me to improve my codes..that if they will input wrong ans. the problem will remain the same..?
Why do not you contact a VB expert? Check http://k.aplis.net/
Reply:Simple enough. I've even got two methods for you. First method:
Initialize a boolean flag variable at the top of btnNext.click's procedure to false. Whenever you test if the user entered the wrong answer, modify the flag accordingly (true if answer was right, false if wrong). Down where you change the numbers (ie a = (50*rnd) b = (49*rnd)), put an if...then block around it, where at you test the flag for truth or falseness (if booFlag = true then a=(50*rnd) b = (49*rnd)).
The second method, and one I recommend (saves coding) is to simply move the re-definitions of a and b (a=(50*rnd) and all that stuff) into the if..then block (after the pre-existing code for a correct answer) where you test if the user inputted the correct answer. Thus, whenever you test for the correct answer, you will automatically generate a new question if the answer is correct (elsewise it will "fall through the bottom" and the message you sent to lblMessage will tell the user of the problem).
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment